Simplify/Condense log base 15 of 3+ log base 15 of 5

$\log_{15} (3) + \log_{15} (5)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{15} (3 \cdot 5)$

Step 2

Multiply $3$ by $5$ .

$\log_{15} (15)$

Step 3

Logarithm base $15$ of $15$ is $1$ .

$1$