Simplify/Condense log base 3 of 9+ log base 3 of 1/9

$\log_{3} (9) + \log_{3} (\frac{1}{9})$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{3} (9 (\frac{1}{9}))$

Cancel the common factor of $9$ .

Cancel the common factor.

$\log_{3} (9 (\frac{1}{9}))$

Rewrite the expression.

$\log_{3} (1)$

Logarithm base $3$ of $1$ is $0$ .

$0$