Simplify/Condense log base 5 of 125+ log base 5 of 125

$\log_{5} (125) + \log_{5} (125)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{5} (125 \cdot 125)$

Step 2

Multiply $125$ by $125$ .

$\log_{5} (15625)$

Step 3

Logarithm base $5$ of $15625$ is $6$ .

$6$