Simplify/Condense log base 6 of 12+ log base 6 of 3

$\log_{6} (12) + \log_{6} (3)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{6} (12 \cdot 3)$

Step 2

Multiply $12$ by $3$ .

$\log_{6} (36)$

Step 3

Logarithm base $6$ of $36$ is $2$ .

$2$