Simplify/Condense log base 6 of 8+ log base 6 of 27

$\log_{6} (8) + \log_{6} (27)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{6} (8 \cdot 27)$

Multiply $8$ by $27$ .

$\log_{6} (216)$

Logarithm base $6$ of $216$ is $3$ .

$3$