Simplify/Condense log base 8 of 4+ log base 8 of 16

$\log_{8} (4) + \log_{8} (16)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{8} (4 \cdot 16)$

Step 2

Multiply $4$ by $16$ .

$\log_{8} (64)$

Step 3

Logarithm base $8$ of $64$ is $2$ .

$2$