Simplify/Condense log of y+12 log of z

$\log (y) + 12 \log (z)$

Step 1

Simplify $12 \log (z)$ by moving $12$ inside the logarithm.

$\log (y) + \log (z^{12})$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (y z^{12})$