Simplify cube root of -250x^6y^5

$\sqrt[3]{- 250 x^{6} y^{5}}$

Step 1

Rewrite $- 250 x^{6} y^{5}$ as ${(- 5 x^{2} y)}^{3} \cdot (2 y^{2})$ .

Factor $- 125$ out of $- 250$ .

$\sqrt[3]{- 125 (2) x^{6} y^{5}}$

Rewrite $- 125$ as ${(- 5)}^{3}$ .

$\sqrt[3]{{(- 5)}^{3} \cdot 2 x^{6} y^{5}}$

Rewrite $x^{6}$ as ${(x^{2})}^{3}$ .

$\sqrt[3]{{(- 5)}^{3} \cdot 2 {(x^{2})}^{3} y^{5}}$

Factor out $y^{3}$ .

$\sqrt[3]{{(- 5)}^{3} \cdot 2 {(x^{2})}^{3} (y^{3} y^{2})}$

Move $2$ .

$\sqrt[3]{{(- 5)}^{3} {(x^{2})}^{3} y^{3} \cdot 2 y^{2}}$

Rewrite ${(- 5)}^{3} {(x^{2})}^{3} y^{3}$ as ${(- 5 x^{2} y)}^{3}$ .

$\sqrt[3]{{(- 5 x^{2} y)}^{3} \cdot 2 y^{2}}$

Add parentheses.

$\sqrt[3]{{(- 5 x^{2} y)}^{3} \cdot (2 y^{2})}$

Step 2

Pull terms out from under the radical.

$- 5 x^{2} y \sqrt[3]{2 y^{2}}$