Simplify cube root of 256x^6

$\sqrt[3]{256 x^{6}}$

Step 1

Rewrite $256 x^{6}$ as ${(4 x^{2})}^{3} \cdot 4$ .

Factor $64$ out of $256$ .

$\sqrt[3]{64 (4) x^{6}}$

Rewrite $64$ as $4^{3}$ .

$\sqrt[3]{4^{3} \cdot 4 x^{6}}$

Rewrite $x^{6}$ as ${(x^{2})}^{3}$ .

$\sqrt[3]{4^{3} \cdot 4 {(x^{2})}^{3}}$

Move $4$ .

$\sqrt[3]{4^{3} {(x^{2})}^{3} \cdot 4}$

Rewrite $4^{3} {(x^{2})}^{3}$ as ${(4 x^{2})}^{3}$ .

$\sqrt[3]{{(4 x^{2})}^{3} \cdot 4}$

Step 2

Pull terms out from under the radical.

$4 x^{2} \sqrt[3]{4}$