Simplify cube root of 27^2

$\sqrt[3]{27^{2}}$

Step 1

Raise $27$ to the power of $2$ .

$\sqrt[3]{729}$

Step 2

Rewrite $729$ as $9^{3}$ .

$\sqrt[3]{9^{3}}$

Step 3

Pull terms out from under the radical, assuming real numbers.

$9$