Simplify cube root of 27e^(6x)

$\sqrt[3]{27 e^{6 x}}$

Step 1

Rewrite $27 e^{6 x}$ as ${(3 e^{2 x})}^{3}$ .

$\sqrt[3]{{(3 e^{2 x})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$3 e^{2 x}$

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