Simplify cube root of 27r^15s^18

$\sqrt[3]{27 r^{15} s^{18}}$

Step 1

Rewrite $27 r^{15} s^{18}$ as ${(3 r^{5} s^{6})}^{3}$ .

$\sqrt[3]{{(3 r^{5} s^{6})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$3 r^{5} s^{6}$

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