Simplify cube root of 27x^6y^9

$\sqrt[3]{27 x^{6} y^{9}}$

Step 1

Rewrite $27 x^{6} y^{9}$ as ${(3 x^{2} y^{3})}^{3}$ .

$\sqrt[3]{{(3 x^{2} y^{3})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$3 x^{2} y^{3}$

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