Simplify cube root of 27y^6

$\sqrt[3]{27 y^{6}}$

Step 1

Rewrite $27 y^{6}$ as ${(3 y^{2})}^{3}$ .

$\sqrt[3]{{(3 y^{2})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$3 y^{2}$

Related Questions