Simplify ( cube root of -5)/(40^(1/3))

$\frac{\sqrt[3]{- 5}}{40^{\frac{1}{3}}}$

Simplify the numerator.

Rewrite $- 5$ as ${(- 1)}^{3} \cdot 5$ .

Rewrite $- 5$ as $- 1 (5)$ .

$\frac{\sqrt[3]{- 1 (5)}}{40^{\frac{1}{3}}}$

Rewrite $- 1$ as ${(- 1)}^{3}$ .

$\frac{\sqrt[3]{{(- 1)}^{3} \cdot 5}}{40^{\frac{1}{3}}}$

Pull terms out from under the radical.

$\frac{- 1 \sqrt[3]{5}}{40^{\frac{1}{3}}}$

Rewrite $- 1 \sqrt[3]{5}$ as $- \sqrt[3]{5}$ .

$\frac{- \sqrt[3]{5}}{40^{\frac{1}{3}}}$

Move the negative in front of the fraction.

$- \frac{\sqrt[3]{5}}{40^{\frac{1}{3}}}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{\sqrt[3]{5}}{40^{\frac{1}{3}}}$

Decimal Form:

$- 0.5$