Simplify - cube root of 64y^6

$- \sqrt[3]{64 y^{6}}$

Step 1

Rewrite $64 y^{6}$ as ${(4 y^{2})}^{3}$ .

$- \sqrt[3]{{(4 y^{2})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$- (4 y^{2})$

Step 3

Multiply $4$ by $- 1$ .

$- 4 y^{2}$

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