Simplify cube root of 8x^3y^2

$\sqrt[3]{8 x^{3} y^{2}}$

Step 1

Rewrite $8 x^{3} y^{2}$ as ${(2 x)}^{3} y^{2}$ .

Rewrite $8$ as $2^{3}$ .

$\sqrt[3]{2^{3} x^{3} y^{2}}$

Rewrite $2^{3} x^{3}$ as ${(2 x)}^{3}$ .

$\sqrt[3]{{(2 x)}^{3} y^{2}}$

$\sqrt[3]{{(2 x)}^{3} y^{2}}$

Step 2

Pull terms out from under the radical.

$2 x \sqrt[3]{y^{2}}$

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