Simplify cube root of 8x^3y^6

$\sqrt[3]{8 x^{3} y^{6}}$

Step 1

Rewrite $8 x^{3} y^{6}$ as ${(2 x y^{2})}^{3}$ .

$\sqrt[3]{{(2 x y^{2})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$2 x y^{2}$

Related Questions