Simplify cube root of -8x^6y^12

$\sqrt[3]{- 8 x^{6} y^{12}}$

Step 1

Rewrite $- 8 x^{6} y^{12}$ as ${(- 2 x^{2} y^{4})}^{3}$ .

$\sqrt[3]{{(- 2 x^{2} y^{4})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$- 2 x^{2} y^{4}$