Simplify cube root of 8y^6

$\sqrt[3]{8 y^{6}}$

Step 1

Rewrite $8 y^{6}$ as ${(2 y^{2})}^{3}$ .

$\sqrt[3]{{(2 y^{2})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$2 y^{2}$

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