Simplify cube root of p^6q^24

$\sqrt[3]{p^{6} q^{24}}$

Step 1

Rewrite $p^{6} q^{24}$ as ${(p^{2} q^{8})}^{3}$ .

$\sqrt[3]{{(p^{2} q^{8})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$p^{2} q^{8}$

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