Simplify cube root of s^12t^18

$\sqrt[3]{s^{12} t^{18}}$

Step 1

Rewrite $s^{12} t^{18}$ as ${(s^{4} t^{6})}^{3}$ .

$\sqrt[3]{{(s^{4} t^{6})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$s^{4} t^{6}$

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