Simplify cube root of (s^-3)/(s^-4)

$\sqrt[3]{\frac{s^{- 3}}{s^{- 4}}}$

Step 1

Move $s^{- 4}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\sqrt[3]{s^{- 3} s^{4}}$

Step 2

Multiply $s^{- 3}$ by $s^{4}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sqrt[3]{s^{- 3 + 4}}$

Add $- 3$ and $4$ .

$\sqrt[3]{s^{1}}$

Step 3

Simplify $s^{1}$ .

$\sqrt[3]{s}$