Simplify cube root of x^36

$\sqrt[3]{x^{36}}$

Step 1

Rewrite $x^{36}$ as ${(x^{12})}^{3}$ .

$\sqrt[3]{{(x^{12})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$x^{12}$

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