Simplify cube root of x^7

$\sqrt[3]{x^{7}}$

Step 1

Rewrite $x^{7}$ as ${(x^{2})}^{3} x$ .

Factor out $x^{6}$ .

$\sqrt[3]{x^{6} x}$

Rewrite $x^{6}$ as ${(x^{2})}^{3}$ .

$\sqrt[3]{{(x^{2})}^{3} x}$

$\sqrt[3]{{(x^{2})}^{3} x}$

Step 2

Pull terms out from under the radical.

$x^{2} \sqrt[3]{x}$

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