Simplify cube root of y^14

$\sqrt[3]{y^{14}}$

Step 1

Rewrite $y^{14}$ as ${(y^{4})}^{3} y^{2}$ .

Factor out $y^{12}$ .

$\sqrt[3]{y^{12} y^{2}}$

Rewrite $y^{12}$ as ${(y^{4})}^{3}$ .

$\sqrt[3]{{(y^{4})}^{3} y^{2}}$

$\sqrt[3]{{(y^{4})}^{3} y^{2}}$

Step 2

Pull terms out from under the radical.

$y^{4} \sqrt[3]{y^{2}}$

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