Simplify cube root of y^16

$\sqrt[3]{y^{16}}$

Step 1

Rewrite $y^{16}$ as ${(y^{5})}^{3} y$ .

Factor out $y^{15}$ .

$\sqrt[3]{y^{15} y}$

Rewrite $y^{15}$ as ${(y^{5})}^{3}$ .

$\sqrt[3]{{(y^{5})}^{3} y}$

Step 2

Pull terms out from under the radical.

$y^{5} \sqrt[3]{y}$