Simplify g^-1(7)

$g^{- 1} (7)$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{g} \cdot 7$

Step 2

Combine $\frac{1}{g}$ and $7$ .

$\frac{7}{g}$

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