Simplify i^24*i^47

$i^{24} \cdot i^{47}$

Step 1

Rewrite $i^{24}$ as ${(i^{4})}^{6}$ .

${(i^{4})}^{6} \cdot i^{47}$

Step 2

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

${({(i^{2})}^{2})}^{6} \cdot i^{47}$

Rewrite $i^{2}$ as $- 1$ .

${({(- 1)}^{2})}^{6} \cdot i^{47}$

Raise $- 1$ to the power of $2$ .

$1^{6} \cdot i^{47}$

$1^{6} \cdot i^{47}$

Step 3

One to any power is one.

$1 \cdot i^{47}$

Step 4

Multiply $i^{47}$ by $1$ .

$i^{47}$

Step 5

Rewrite $i^{47}$ as ${(i^{4})}^{11} (i^{2} \cdot i)$ .

Factor out $i^{44}$ .

$i^{44} i^{3}$

Rewrite $i^{44}$ as ${(i^{4})}^{11}$ .

${(i^{4})}^{11} i^{3}$

Factor out $i^{2}$ .

${(i^{4})}^{11} (i^{2} \cdot i)$

${(i^{4})}^{11} (i^{2} \cdot i)$

Step 6

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

${({(i^{2})}^{2})}^{11} (i^{2} \cdot i)$

Rewrite $i^{2}$ as $- 1$ .

${({(- 1)}^{2})}^{11} (i^{2} \cdot i)$

Raise $- 1$ to the power of $2$ .

$1^{11} (i^{2} \cdot i)$

$1^{11} (i^{2} \cdot i)$

Step 7

One to any power is one.

$1 (i^{2} \cdot i)$

Step 8

Multiply $i^{2} \cdot i$ by $1$ .

$i^{2} \cdot i$

Step 9

Rewrite $i^{2}$ as $- 1$ .

$- 1 \cdot i$

Step 10

Rewrite $- 1 i$ as $- i$ .

$- i$

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