Simplify i^-29

$i^{- 29}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{i^{29}}$

Step 2

Simplify the denominator.

Rewrite $i^{29}$ as ${(i^{4})}^{7} i$ .

Factor out $i^{28}$ .

$\frac{1}{i^{28} i}$

Rewrite $i^{28}$ as ${(i^{4})}^{7}$ .

$\frac{1}{{(i^{4})}^{7} i}$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$\frac{1}{{({(i^{2})}^{2})}^{7} i}$

Rewrite $i^{2}$ as $- 1$ .

$\frac{1}{{({(- 1)}^{2})}^{7} i}$

Raise $- 1$ to the power of $2$ .

$\frac{1}{1^{7} i}$

One to any power is one.

$\frac{1}{1 i}$

Multiply $i$ by $1$ .

$\frac{1}{i}$