Simplify (k^-2)^9

${(k^{- 2})}^{9}$

Step 1

Multiply the exponents in ${(k^{- 2})}^{9}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$k^{- 2 \cdot 9}$

Multiply $- 2$ by $9$ .

$k^{- 18}$

Step 2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{k^{18}}$