Simplify (m+1)/(3m-15)*(8m-80)/(m^2-9m-10)

$\frac{m + 1}{3 m - 15} \cdot \frac{8 m - 80}{m^{2} - 9 m - 10}$

Simplify with factoring out.

Factor $3$ out of $3 m - 15$ .

Factor $3$ out of $3 m$ .

$\frac{m + 1}{3 (m) - 15} \cdot \frac{8 m - 80}{m^{2} - 9 m - 10}$

Factor $3$ out of $- 15$ .

$\frac{m + 1}{3 m + 3 \cdot - 5} \cdot \frac{8 m - 80}{m^{2} - 9 m - 10}$

Factor $3$ out of $3 m + 3 \cdot - 5$ .

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 m - 80}{m^{2} - 9 m - 10}$

Factor $8$ out of $8 m - 80$ .

Factor $8$ out of $8 m$ .

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 (m) - 80}{m^{2} - 9 m - 10}$

Factor $8$ out of $- 80$ .

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 m + 8 \cdot - 10}{m^{2} - 9 m - 10}$

Factor $8$ out of $8 m + 8 \cdot - 10$ .

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 (m - 10)}{m^{2} - 9 m - 10}$

Factor $m^{2} - 9 m - 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 10$ and whose sum is $- 9$ .

$- 10, 1$

Write the factored form using these integers.

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 (m - 10)}{(m - 10) (m + 1)}$

Simplify terms.

Cancel the common factor of $m + 1$ .

Factor $m + 1$ out of $(m - 10) (m + 1)$ .

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 (m - 10)}{(m + 1) (m - 10)}$

Cancel the common factor.

$\frac{m + 1}{3 (m - 5)} \cdot \frac{8 (m - 10)}{(m + 1) (m - 10)}$

Rewrite the expression.

$\frac{1}{3 (m - 5)} \cdot \frac{8 (m - 10)}{m - 10}$

Multiply $\frac{1}{3 (m - 5)}$ by $\frac{8 (m - 10)}{m - 10}$ .

$\frac{8 (m - 10)}{3 (m - 5) (m - 10)}$

Cancel the common factor of $m - 10$ .

Cancel the common factor.

$\frac{8 (m - 10)}{3 (m - 5) (m - 10)}$

Rewrite the expression.

$\frac{8}{3 (m - 5)}$

Simplify (m+1)/(3m-15)*(8m-80)/(m^2-9m-10)

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