Simplify (n^3)^3*2n^-1

${(n^{3})}^{3} \cdot 2 n^{- 1}$

Rewrite using the commutative property of multiplication.

$2 {(n^{3})}^{3} n^{- 1}$

Multiply the exponents in ${(n^{3})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$2 n^{3 \cdot 3} n^{- 1}$

Multiply $3$ by $3$ .

$2 n^{9} n^{- 1}$

Multiply $n^{9}$ by $n^{- 1}$ by adding the exponents.

Move $n^{- 1}$ .

$2 (n^{- 1} n^{9})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 n^{- 1 + 9}$

Add $- 1$ and $9$ .

$2 n^{8}$