Simplify natural log of e^(x+1)

$\ln (e^{x + 1})$

Use logarithm rules to move $x + 1$ out of the exponent.

$(x + 1) \ln (e)$

The natural logarithm of $e$ is $1$ .

$(x + 1) \cdot 1$

Multiply $x + 1$ by $1$ .

$x + 1$