Simplify (p^-9q^-4)/(r^2s^-3)

$\frac{p^{- 9} q^{- 4}}{r^{2} s^{- 3}}$

Step 1

Move $p^{- 9}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{q^{- 4}}{r^{2} s^{- 3} p^{9}}$

Step 2

Move $q^{- 4}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{r^{2} s^{- 3} p^{9} q^{4}}$

Step 3

Move $s^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{s^{3}}{r^{2} p^{9} q^{4}}$