Simplify square root of 11y^14z

$\sqrt{11 y^{14} z}$

Rewrite $11 y^{14} z$ as ${(y^{7})}^{2} \cdot (11 z)$ .

Rewrite $y^{14}$ as ${(y^{7})}^{2}$ .

$\sqrt{11 {(y^{7})}^{2} z}$

Reorder $11$ and ${(y^{7})}^{2}$ .

$\sqrt{{(y^{7})}^{2} \cdot 11 z}$

Add parentheses.

$\sqrt{{(y^{7})}^{2} \cdot (11 z)}$

Pull terms out from under the radical.

$y^{7} \sqrt{11 z}$