Simplify square root of 13* square root of -6

$\sqrt{13} \cdot \sqrt{- 6}$

Rewrite $- 6$ as $- 1 (6)$ .

$\sqrt{13} \cdot \sqrt{- 1 (6)}$

Rewrite $\sqrt{- 1 (6)}$ as $\sqrt{- 1} \cdot \sqrt{6}$ .

$\sqrt{13} \cdot (\sqrt{- 1} \cdot \sqrt{6})$

Rewrite $\sqrt{- 1}$ as $i$ .

$\sqrt{13} \cdot (i \cdot \sqrt{6})$

Multiply $\sqrt{13} (i \sqrt{6})$ .

Combine using the product rule for radicals.

$\sqrt{6 \cdot 13} i$

Multiply $6$ by $13$ .

$\sqrt{78} i$