Simplify square root of 14xy^10

$\sqrt{14 x y^{10}}$

Step 1

Rewrite $14 x y^{10}$ as ${(y^{5})}^{2} \cdot (14 x)$ .

Rewrite $y^{10}$ as ${(y^{5})}^{2}$ .

$\sqrt{14 x {(y^{5})}^{2}}$

Move $x$ .

$\sqrt{14 {(y^{5})}^{2} x}$

Reorder $14$ and ${(y^{5})}^{2}$ .

$\sqrt{{(y^{5})}^{2} \cdot 14 x}$

Add parentheses.

$\sqrt{{(y^{5})}^{2} \cdot (14 x)}$

Step 2

Pull terms out from under the radical.

$y^{5} \sqrt{14 x}$