Simplify square root of 16y^8

$\sqrt{16 y^{8}}$

Rewrite $16 y^{8}$ as ${(4 y^{4})}^{2}$ .

$\sqrt{{(4 y^{4})}^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$4 y^{4}$

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