Simplify square root of 2^(4x-6)

$\sqrt{2^{4 x - 6}}$

Step 1

Rewrite $2^{4 x - 6}$ as ${(2^{2 x - 3})}^{2}$ .

$\sqrt{{(2^{2 x - 3})}^{2}}$

Step 2

Pull terms out from under the radical, assuming positive real numbers.

$2^{2 x - 3}$

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