Simplify square root of 2^6* fourth root of 4

$\sqrt{2^{6}} \cdot \sqrt[4]{4}$

Step 1

Raise $2$ to the power of $6$ .

$\sqrt{64} \cdot \sqrt[4]{4}$

Step 2

Rewrite $64$ as $8^{2}$ .

$\sqrt{8^{2}} \cdot \sqrt[4]{4}$

Step 3

Pull terms out from under the radical, assuming positive real numbers.

$8 \cdot \sqrt[4]{4}$

Step 4

Rewrite $4$ as $2^{2}$ .

$8 \cdot \sqrt[4]{2^{2}}$

Step 5

Rewrite $\sqrt[4]{2^{2}}$ as $\sqrt{\sqrt{2^{2}}}$ .

$8 \cdot \sqrt{\sqrt{2^{2}}}$

Step 6

Pull terms out from under the radical, assuming positive real numbers.

$8 \sqrt{2}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$8 \sqrt{2}$

Decimal Form:

$11.31370849 \dots$