Simplify square root of 20h^6k^4

$\sqrt{20 h^{6} k^{4}}$

Step 1

Rewrite $20 h^{6} k^{4}$ as ${(2 h^{3} k^{2})}^{2} \cdot 5$ .

Factor $4$ out of $20$ .

$\sqrt{4 (5) h^{6} k^{4}}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 5 h^{6} k^{4}}$

Rewrite $h^{6}$ as ${(h^{3})}^{2}$ .

$\sqrt{2^{2} \cdot 5 {(h^{3})}^{2} k^{4}}$

Rewrite $k^{4}$ as ${(k^{2})}^{2}$ .

$\sqrt{2^{2} \cdot 5 {(h^{3})}^{2} {(k^{2})}^{2}}$

Move $5$ .

$\sqrt{2^{2} {(h^{3})}^{2} {(k^{2})}^{2} \cdot 5}$

Rewrite $2^{2} {(h^{3})}^{2} {(k^{2})}^{2}$ as ${(2 h^{3} k^{2})}^{2}$ .

$\sqrt{{(2 h^{3} k^{2})}^{2} \cdot 5}$

Step 2

Pull terms out from under the radical.

$2 h^{3} k^{2} \sqrt{5}$