Simplify - square root of 20xy^2

$- \sqrt{20 x y^{2}}$

Step 1

Rewrite $20 x y^{2}$ as ${(2 y)}^{2} \cdot (5 x)$ .

Factor $4$ out of $20$ .

$- \sqrt{4 (5) x y^{2}}$

Rewrite $4$ as $2^{2}$ .

$- \sqrt{2^{2} \cdot 5 x y^{2}}$

Move $x$ .

$- \sqrt{2^{2} \cdot 5 y^{2} x}$

Move $5$ .

$- \sqrt{2^{2} y^{2} \cdot 5 x}$

Rewrite $2^{2} y^{2}$ as ${(2 y)}^{2}$ .

$- \sqrt{{(2 y)}^{2} \cdot 5 x}$

Add parentheses.

$- \sqrt{{(2 y)}^{2} \cdot (5 x)}$

Step 2

Pull terms out from under the radical.

$- (2 y \sqrt{5 x})$

Step 3

Multiply $2$ by $- 1$ .

$- 2 y \sqrt{5 x}$