Simplify square root of 252x^8y^19

$\sqrt{252 x^{8} y^{19}}$

Step 1

Rewrite $252 x^{8} y^{19}$ as ${(6 x^{4} y^{9})}^{2} \cdot (7 y)$ .

Factor $36$ out of $252$ .

$\sqrt{36 (7) x^{8} y^{19}}$

Rewrite $36$ as $6^{2}$ .

$\sqrt{6^{2} \cdot 7 x^{8} y^{19}}$

Rewrite $x^{8}$ as ${(x^{4})}^{2}$ .

$\sqrt{6^{2} \cdot 7 {(x^{4})}^{2} y^{19}}$

Factor out $y^{18}$ .

$\sqrt{6^{2} \cdot 7 {(x^{4})}^{2} (y^{18} y)}$

Rewrite $y^{18}$ as ${(y^{9})}^{2}$ .

$\sqrt{6^{2} \cdot 7 {(x^{4})}^{2} ({(y^{9})}^{2} y)}$

Move $7$ .

$\sqrt{6^{2} {(x^{4})}^{2} {(y^{9})}^{2} \cdot 7 y}$

Rewrite $6^{2} {(x^{4})}^{2} {(y^{9})}^{2}$ as ${(6 x^{4} y^{9})}^{2}$ .

$\sqrt{{(6 x^{4} y^{9})}^{2} \cdot 7 y}$

Add parentheses.

$\sqrt{{(6 x^{4} y^{9})}^{2} \cdot (7 y)}$

Step 2

Pull terms out from under the radical.

$6 x^{4} y^{9} \sqrt{7 y}$