Simplify square root of 28x^10

$\sqrt{28 x^{10}}$

Step 1

Rewrite $28 x^{10}$ as ${(2 x^{5})}^{2} \cdot 7$ .

Factor $4$ out of $28$ .

$\sqrt{4 (7) x^{10}}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 7 x^{10}}$

Rewrite $x^{10}$ as ${(x^{5})}^{2}$ .

$\sqrt{2^{2} \cdot 7 {(x^{5})}^{2}}$

Move $7$ .

$\sqrt{2^{2} {(x^{5})}^{2} \cdot 7}$

Rewrite $2^{2} {(x^{5})}^{2}$ as ${(2 x^{5})}^{2}$ .

$\sqrt{{(2 x^{5})}^{2} \cdot 7}$

Step 2

Pull terms out from under the radical.

$2 x^{5} \sqrt{7}$