Simplify square root of 28x+ square root of 63x

$\sqrt{28 x} + \sqrt{63 x}$

Step 1

Simplify each term.

Rewrite $28 x$ as $2^{2} \cdot (7 x)$ .

Factor $4$ out of $28$ .

$\sqrt{4 (7) x} + \sqrt{63 x}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 7 x} + \sqrt{63 x}$

Add parentheses.

$\sqrt{2^{2} \cdot (7 x)} + \sqrt{63 x}$

$\sqrt{2^{2} \cdot (7 x)} + \sqrt{63 x}$

Pull terms out from under the radical.

$2 \sqrt{7 x} + \sqrt{63 x}$

Rewrite $63 x$ as $3^{2} \cdot (7 x)$ .

Factor $9$ out of $63$ .

$2 \sqrt{7 x} + \sqrt{9 (7) x}$

Rewrite $9$ as $3^{2}$ .

$2 \sqrt{7 x} + \sqrt{3^{2} \cdot 7 x}$

Add parentheses.

$2 \sqrt{7 x} + \sqrt{3^{2} \cdot (7 x)}$

$2 \sqrt{7 x} + \sqrt{3^{2} \cdot (7 x)}$

Pull terms out from under the radical.

$2 \sqrt{7 x} + 3 \sqrt{7 x}$

$2 \sqrt{7 x} + 3 \sqrt{7 x}$

Step 2

Add $2 \sqrt{7 x}$ and $3 \sqrt{7 x}$ .

$5 \sqrt{7 x}$

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