Simplify square root of 3* cube root of 4

$\sqrt{3} \cdot \sqrt[3]{4}$

Step 1

Rewrite the expression using the least common index of $6$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$3^{\frac{1}{2}} \sqrt[3]{4}$

Rewrite $3^{\frac{1}{2}}$ as $3^{\frac{3}{6}}$ .

$3^{\frac{3}{6}} \sqrt[3]{4}$

Rewrite $3^{\frac{3}{6}}$ as $\sqrt[6]{3^{3}}$ .

$\sqrt[6]{3^{3}} \sqrt[3]{4}$

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{4}$ as $4^{\frac{1}{3}}$ .

$\sqrt[6]{3^{3}} \cdot 4^{\frac{1}{3}}$

Rewrite $4^{\frac{1}{3}}$ as $4^{\frac{2}{6}}$ .

$\sqrt[6]{3^{3}} \cdot 4^{\frac{2}{6}}$

Rewrite $4^{\frac{2}{6}}$ as $\sqrt[6]{4^{2}}$ .

$\sqrt[6]{3^{3}} \sqrt[6]{4^{2}}$

Step 2

Combine using the product rule for radicals.

$\sqrt[6]{3^{3} \cdot 4^{2}}$

Step 3

Raise $3$ to the power of $3$ .

$\sqrt[6]{27 \cdot 4^{2}}$

Step 4

Raise $4$ to the power of $2$ .

$\sqrt[6]{27 \cdot 16}$

Step 5

Multiply $27$ by $16$ .

$\sqrt[6]{432}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$\sqrt[6]{432}$

Decimal Form:

$2.74945927 \dots$