Simplify square root of 80x^2

$\sqrt{80 x^{2}}$

Step 1

Rewrite $80 x^{2}$ as ${(4 x)}^{2} \cdot 5$ .

Factor $16$ out of $80$ .

$\sqrt{16 (5) x^{2}}$

Rewrite $16$ as $4^{2}$ .

$\sqrt{4^{2} \cdot 5 x^{2}}$

Move $5$ .

$\sqrt{4^{2} x^{2} \cdot 5}$

Rewrite $4^{2} x^{2}$ as ${(4 x)}^{2}$ .

$\sqrt{{(4 x)}^{2} \cdot 5}$

$\sqrt{{(4 x)}^{2} \cdot 5}$

Step 2

Pull terms out from under the radical.

$4 x \sqrt{5}$

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