Simplify square root of -8x

$\sqrt{- 8 x}$

Step 1

Rewrite $- 8 x$ as $2^{2} \cdot (- 2 x)$ .

Factor $4$ out of $- 8$ .

$\sqrt{4 (- 2) x}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot - 2 x}$

Add parentheses.

$\sqrt{2^{2} \cdot (- 2 x)}$

$\sqrt{2^{2} \cdot (- 2 x)}$

Step 2

Pull terms out from under the radical.

$2 \sqrt{- 2 x}$

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