Simplify square root of 8x* square root of 4x* square root of 3x

$\sqrt{8 x} \cdot \sqrt{4 x} \cdot \sqrt{3 x}$

Step 1

Rewrite $8 x$ as $2^{2} \cdot (2 x)$ .

Factor $4$ out of $8$ .

$\sqrt{4 (2) x} \cdot \sqrt{4 x} \cdot \sqrt{3 x}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 2 x} \cdot \sqrt{4 x} \cdot \sqrt{3 x}$

Add parentheses.

$\sqrt{2^{2} \cdot (2 x)} \cdot \sqrt{4 x} \cdot \sqrt{3 x}$

Step 2

Pull terms out from under the radical.

$2 \sqrt{2 x} \cdot \sqrt{4 x} \cdot \sqrt{3 x}$

Step 3

Rewrite $4$ as $2^{2}$ .

$2 \sqrt{2 x} \cdot \sqrt{2^{2} x} \cdot \sqrt{3 x}$

Step 4

Pull terms out from under the radical.

$2 \sqrt{2 x} \cdot (2 \sqrt{x}) \cdot \sqrt{3 x}$

Step 5

Multiply $2 \sqrt{2 x} (2 \sqrt{x})$ .

Multiply $2$ by $2$ .

$4 \sqrt{2 x} \sqrt{x} \cdot \sqrt{3 x}$

Combine using the product rule for radicals.

$4 \sqrt{x (2 x)} \cdot \sqrt{3 x}$

Raise $x$ to the power of $1$ .

$4 \sqrt{2 (x^{1} x)} \cdot \sqrt{3 x}$

Raise $x$ to the power of $1$ .

$4 \sqrt{2 (x^{1} x^{1})} \cdot \sqrt{3 x}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 \sqrt{2 x^{1 + 1}} \cdot \sqrt{3 x}$

Add $1$ and $1$ .

$4 \sqrt{2 x^{2}} \cdot \sqrt{3 x}$

Step 6

Reorder $2$ and $x^{2}$ .

$4 \sqrt{x^{2} \cdot 2} \cdot \sqrt{3 x}$

Step 7

Pull terms out from under the radical.

$4 (x \sqrt{2}) \cdot \sqrt{3 x}$

Step 8

Multiply $4 x \sqrt{2} \sqrt{3 x}$ .

Combine using the product rule for radicals.

$4 x \sqrt{3 x \cdot 2}$

Multiply $2$ by $3$ .

$4 x \sqrt{6 x}$